if roots of x square +kx+k=0 are real and equal what is the value of k?
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this is the answer of this question
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ayushvishwakarma50:
hey i appreciate your participation towards my question but the answer that you gave is incorrect
The answer is 0and4
But thank you very much
sorry ooo!!
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Answer:
Step-by-step explanation:
D=(b)^2 -4ac.( d is equal 0)
0=k^2-4k
4k=k^2
√4k=k
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