Question

if roots of x³-kx²+14x-8=0 are in gp then k=​

Answer 1

Step-by-step explanation:

answer

7

solution

$let \: \frac{a}{r} \: \: a \: \: ar \: the \: roots$

$\frac{a}{r} .a.ar = 8 \\ a {}^{3 } = 8 \: a = 2$

therefore, a=2 is a root of given equation

so, 2³ -k. 2²+14.2-8=0

= 8-4k+28-8=0

=k=7