Question

If rotational kinetic energy is 50 percent of translational energy then body is

Answer 1

If rotational kinetic energy is 50% of total kinetic energy then the body will be:-

1.Ring

2.Cylinder

3.Hollow sphere

4.Solid sphere

Answer 2

Given :

Rotational kinetic energy is 50 percent of translational energy .

To Find :

The shape of body .

Solution :

We know , translational energy is given by :

$T.E=\dfrac{I\omega^2}{2}$

Also , rotational energy is given by :

$R.E=\dfrac{mv^2}{2}$

Also , we know , $v=\omega R$

So , by given condition .

$R.E=\dfrac{K.E}{2}\\\\\dfrac{I\omega^2}{2}=\dfrac{mv^2}{4}\\\\\dfrac{I\omega^2}{2}=\dfrac{m(\omega R)^2}{4}\\\\I=\dfrac{mR^2}{2}$

Therefore , the object can be cylinder and circular disk .

Learn More :

Rotational Motion

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