Question

if Rs. 1800 is invested at 10%pa compounded anually for two years . What will be the amount ?​

Answer 1

Answer:

Rs2178

Step-by-step explanation:

A=p(1+r/100)^n

A=1800(1+10/100)^2

A=1800(1+1/10)^2

A=1800×11/10×11/10

A=18×11×11

A=RS2178

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Answer 2

Given :-  

• Rs. 1800 is invested at 10%p.a. compounded annually for two years .

 

To Find :-  

• What will be the amount ?  

Solution :-  

~Here, we’re given the principal , rate and time for which the money is invested and we need to find the amount after the given time. We can easily find the amount by putting the values in it’s formula.

In this question,  

• The principal  ( P ) is Rs. 1800  
• The rate ( R ) is 10 %  
• The time ( n )  is 2 years  
• The amount will be ( A )  

 Formula :-

$\sf \bullet \;\; A = P \bigg \{ 1 + \dfrac{R}{100} \bigg \}^{n}$

By putting the values !  

$\sf \implies A = 1,800 \bigg \{ 1 + \dfrac{10}{100} \bigg \}^{2}$

$\sf \implies A = 1,800 \bigg \{ 1 + \dfrac{110}{100} \bigg \}^{2}$

$\sf \implies A = 1,800 \bigg \{ \dfrac{11}{10} \bigg \}^{2}$

$\sf \implies A = 1,800 \times \dfrac{11}{10} \times \dfrac{11}{10}$

 

$\sf \implies A = 18 \times 11 \times 11$

$\sf \implies A = Rs. \; 2,178$

Therefore,  

• The amount will be Rs. 2,178