if RS and PT are altitudes of a triangle PQR. prove that (1). triangle PQT is similar to triangle QRS (2). PQ*QS=RQ*QT
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hey here is your solution
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raavi6:
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Altitudes of ΔPQR = RS and PT
1. In ΔPQT and ΔQRS,
∠PTQ = ∠RSQ = 90° (Given)
∠PQT = ∠RQS (Common angle)
ΔPQT ~ Δ RQS (By similarity AA)
2. Since ΔPQT and ΔRQS are similar
Thus,
PQ/RQ = QT/QS
= PQ × QS = RQ × QT
Hence proved
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