Question

If Rth terms of an AP is S and S term of the AP is R, then what is the value of (R+ S) th term of the AP?
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Answer 1

Rth =S

TR =a+(R-1)×D=S

=a+RD-D...........(i)

and

Sth=R

TS=a+(S-1)×D

=a+SD-D=R.............(ii)

equation (i)&(ii).. we get,

a+RD-D=S |

a+Sd-D=R | ON SUBTRACTING

- - + -

------------------------

-SD-RD=S-R

-D(S-R)=S-R

-D =S-R

------

S-R

D = -1

.•. PUTTING THE VALUE OF D IN EQUATION (i),weget

a+RD-D=S

a+R×1-1=S

a+R-1=S

a=S-R+1

A/c

t(R+S)=a+(R+S-1)×D

=S-R+1×R+S-1×1

=s-s+R-R+1-1×1

=0×1

=0 Answer.

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