if rupees 1440 is divided into two parts in which one part is 7 9th of the second then the smaller part is
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Answered by
2
Let the larger part = x
Then, the smaller part =7x/9
Therefore,
x+7x/9=1440
16x/9=1440
16x=1440 X 9
x=(1440 X 9)/16
x=810
Therefore, the smaller part is 7x/9= 7*810/9= Rs 630
Then, the smaller part =7x/9
Therefore,
x+7x/9=1440
16x/9=1440
16x=1440 X 9
x=(1440 X 9)/16
x=810
Therefore, the smaller part is 7x/9= 7*810/9= Rs 630
Answered by
0
the answer is 18
1440=X+Y....eq-1
X=79Y....eq-2
substituting X=79Y in equation 1
1440=X+79X
1440=80X
X=1440/80
X=18rs
1440=X+Y....eq-1
X=79Y....eq-2
substituting X=79Y in equation 1
1440=X+79X
1440=80X
X=1440/80
X=18rs
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