Question

If s=20m,v=4m/s,u=0find the acceleration

Answer 1

Given :

• Distance covered by the body is 20 m
• Final velocity of the body is 4 m/s
• Initial velocity of the body is 0 m/s

To find :

• The acceleration of the body

Solution :

From Third equation of motion ,

$\boxed {\rm{v {}^{2} - {u}^{2} = 2as }}$

Here ,

• s is Distance covered by the body
• v is Final velocity of the body
• u is Initial velocity of the body
• a is Acceleration of the body

$\sf \bigstar {\underline{ \sf{By \: substituting \: the \: values ,\: }}}$

$: \implies \rm \: ( 4 \: m {s}^{ - 1} ){}^{2} - (0 ){}^{2} = 2 (a)(20 \: m) \\ \\ : \implies \rm \: 16 \: m {}^{2} {s}^{ - 2} - 0 = 40 \: m(a) \\ \\ : \implies \rm \: 16 \: m {s}^{ - 2} = 40(a) \\ \\ : \implies \rm \: a = \frac{16 \: m {s}^{ - 2} }{40} \\ \\ : \implies \rm \: a = 0.4 \: m {s}^{ - 2}$

Hence , The acceleration of the given body is 0.4 m/s²

Answer 2

From the equation of motion v^2=u^2+2as

v^2-u^2=2as

Given v=4m/s, u=0, s=20m

now,,,

4^2-0 = 2×a×20

16 =40×a

a =16/40

a =0.4 m/s^2