if s=246 ,a=4 and d=3 find n if s=n÷2{2a+[n-1]d}
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Answer:
24.6
Step-by-step explanation:
246=n/2[2*4+(n-1)3]
492=n(8+3n-3)
492=n*5+3n
492/5=4n
492/5*4=n
n=24.6
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