Question

if s and t are two are two real numbers such that their square is five more than the respective number then s square and t square is equals to?

Answer 1

Answer:

Step-by-step explanation:

S^2 = S +5 eq1

T^2 = T +5 eq2

Eq1-eq2

S^2-T^2 = S+5 - T-5

(S+T)(S-T) = S-T

S+T = 1

Eq 1 + eq2

S^2 + T^2 = S+5 + T+5

S^2 + T^2 = S+T + 10

Putting value of S+T

S^2+T^2 = 1 + 10

S^2 + T^2 = 11