if S and T have N elements in common.
Show that S×T and T×S have n2 elements in common.
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Let S and T have n elements in common.
Then:
(S X T) ∩ (U X V) = (S ∩ U) X (T ∩ V)
It is given that n(S∩T)=n elements
Now n[(S∩T)×(T∩S)]=n.n= elements
Hence proved.
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