Question

If S be the sum of first (2n+1) terms of an A.P. and the sum
of terms in odd positions of these (2n +1) terms be S', then
show that (n+1) S = (2n + 1)S'.​

Answer 1

Answer:

13-Mar-2017 · If S be the sum of (2n+1) terms of an AP and S1 that of alternate terms beginning with the first ,then show that S/S1 =2n+1/n+1.