Question

If S is a point on side PQ of a APQR such that PS = QS = RS, then (a) PR. QR = RS2 (b) QS2 + RS2 = QR (C) PR2 + QR2 = PQ? (d) PS2 + RS2 = PR2​

Answer 1

Answer:

Now in, ∆PQR, sum of angles = 180° ⇒ ∠P + ∠Q + ∠R = 180° ⇒ ∠2 + ∠4 + ∠1 + ∠3 = 180° ⇒ ∠1 + ∠3 + ∠1 + ∠3 = 180° ⇒∠2 (1 + ∠3) = 180° ⇒ ∠1 + ∠3 = (180°)/2 = 90° ∴ ∠R = 90° In ∆PQR, by Pythagoras theorem, PR2 + QR2 = PQ2Read more on Sarthaks.com - https://www.sarthaks.com/881503/if-s-is-a-point-on-side-pq-of-a-pqr-such-that-ps-qs-rs-then