If S is a point on side PQ of a ΔPQR such that PS = QS = RS, then
1 point
(a) PR . QR = RS square
(b) QSsq + RS sq =QRsq
(c) PR sq + QR Sq= PQSq
(d) PS sq+ RS sq= PR sq
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If S is a point on side PQ of a ΔPQR such that PS = QS = RS, then
1 point
(a) PR . QR = RS square
(b) QSsq + RS sq =QRsq
(c) PR sq + QR Sq= PQSq
(d) PS sq+ RS sq= PR sq
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