If s = n/2(2a+(n-1)d) find a) a, when s = 185 n = 10 and d = 3 b) d, when a = 8 s = 380 and n =10
neelimagundu:
mentioning units is important dear,in questions especially as well as answers.
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a) 185=10/2(2a+(5-1)3)
= 5(2a+(4*3))
= 10a+60 (4*3=12; nd 12*5=60)
185-60=10a
125/10=a
∴a=12.5
= 5(2a+(4*3))
= 10a+60 (4*3=12; nd 12*5=60)
185-60=10a
125/10=a
∴a=12.5
yeah.... ! its wrong!!
n=10 not 5
ik.... bt 10/2= 5
answer is::
is?
a) a=5 m/s2
b) d= 60/9 m
a=5
where did m and m/s2 come from?
those are the units for distance(d) and acceleration (a)
Answered by
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As s=n/2(2a +(n-1)d put the value where s=185, n=10 and d=3
185=10/2{2a+(10-1)3}
185=5{2a+(9*3)}
185=5{2a+27}
185=10a+135
185-135=10a
a=50/10
a=5
As given S=380, a=8 and n=10
380=10/2{2*8+(10-1)d}
380=5{16+9d}
380/5=16+9d
76=16+9d
76-16 = 9d
60 = 9d
d = 60/9
d = 6.666
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