If s:r=1/2:1/3 and r:t= 3/2:7/3 . Find s:r:t
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Given, x=2+22/3+21/3
⇒(x−2)=22/3+21/3
⇒(x−2)=22/3+21/3
On cubing both sides, we get
(x−2)3=22+2+3⋅22/3⋅21/3(22/3+21/3)
⇒x3−6x2+12x−8=4+2+3×2×(x−2)
⇒x3−6x2+6x=2.
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