Question

If s(s+s1+s2)=9,s1(s+s1+s2)=16 and s2(s+s1+s2)= 144, then the what is the value of s?

Answer 1

$s(s+s1+s2) = 9$
$this\: means\: s = \frac{9}{(s+s1+s2)}$
$simiarly \: s1 = \frac{16}{(s+s1+s2)}$
$similarly\: s2 = \frac{144}{(s+s1+s2)}$
$(s+s1+s2) = \frac{9}{(s+s1+s2)} + \frac{16}{(s+s1+s2)} + \frac{144}{(s+s1+s2)}$
$(s+s1+s2) = \frac{169}{(s + s1 + s2)}$
${(s+s1+s2)}^{2} = 169$
${(s+s1+s2)} = 13$
So Now from the above equations,

$s = \frac{9}{13}$

$s1 = \frac{16}{13}$

$s2 = \frac{144}{13}$

SO, S=9/14 ; S1=16/13 ; S2=144/13

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