if s= t/2t+1then find ds/ds
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Given that : s = (t/2t+1)
On differentiate with respect to s both the sides :
ds/ds = (2t+1)dt/ds+t(2dt/ds+0)/(2t+1)²
=> ds/ds = dt/ds(2t+1+2t)/(2t+1)²
=> ds/ds = dt/ds(4t+1)/(2t+1)²
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