Question

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s circle t) (negative 7)?

Answer 1

Given : s(x) = 2 – x²  and  t(x) = 3x

To Find :  (sot) (-7)

Solution:

gof (x) = g(f (x))

=> sot (x) = s(t (x))

=>  sot (-7) = s(t (-7))

t(x) = 3x

=> t (-7) = 3(-7)

=> t (-7) = -21

sot (-7) = s(t (-7))

=> sot (-7) = s(-21)

s(x) = 2 – x²

=> s(-21) = 2 - (-21)²

=> s(-21) = 2 - 441

=> s(-21) = -439

sot (-7) = s(-21)

=> sot (-7) = -439

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