Question

If S1= 2+4+....+ 2n and S2 =1+3+....7+ (2n-1), then S1:S2 =? ​

Answer 1

Answer:

(n+1)/n

Step-by-step explanation:

sum of even terms = n(n+1) = S1

and sum of odd = n^2= s2

so,

s1/s2 = n ( n+1 )/ n^2= (n+1)/n

Answer 2

Answer:

if i am correct so plss mark me as a brainlinest