Question

if S1= a 2 + a4 +a 6+....
. upto 100 terms and S2= a 1 + a3 + a5+......upto 100 terms of a certain AP then prove that common difference of this AP is S1 - S2 / 100

Answer 1

............................

Answer 2

Step-by-step explanation:

Sum of first A.P=10100=S₁

sum of second A.P=10000=S₂

Then, S₁-S₂=10100-10000=100

Therefore,S₁-S₂=100

Hence,proved.

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