if S1 ,S2 ,S3 are the sum of n terms of the three ap's.the first term of each being unity and the respective common difference being 1, 2, 3. prove that S1 +S3=2S2
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Formula of summation of an A.P: ,
where = Summation till n terms.
a = First term of sequence
d = Common Difference.
Now, using this formula, we get
S1 = n + n^2 / 2
S2 = n^2
S3 = 3n^2 - n /2
Therefore, to get the desired equation, we add S1 and S3.
∴ S1 + S3 = n + n^2 / 2 + 3n^2 - n /2
= n^2 + 3n^2
= 4n^2 / 2
= 2n^2
= 2(S2).
∴ S1 + S3 = 2(S2).Hence proved.
where = Summation till n terms.
a = First term of sequence
d = Common Difference.
Now, using this formula, we get
S1 = n + n^2 / 2
S2 = n^2
S3 = 3n^2 - n /2
Therefore, to get the desired equation, we add S1 and S3.
∴ S1 + S3 = n + n^2 / 2 + 3n^2 - n /2
= n^2 + 3n^2
= 4n^2 / 2
= 2n^2
= 2(S2).
∴ S1 + S3 = 2(S2).Hence proved.
swati2504:
thanks palaku
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