Question

If S10 = 300 and S9 = 270 in an A.P, then the value of a10 is​

Answer 1

Given:

S₁₀ = 300 and S₉ = 270 in an A.P.

To find:

The value of a₁₀

Solution:

To solve the given problem we will use the following problem:

$\boxed{\boxed{\bold{a_n = S_n - S_(_n_-_1_)}}}$

Where

aₙ = nth term of an A.P.

Sₙ = sum of n terms in A.P.

Sₙ₋₁ = sum of n-1 terms in A.P.

According to the question, we will substitute the value of n = 10 in the above formula and solve it further as follows:

$a_1_0 = S_1_0 - S_(_1_0_-_1_)}}}$

$\implies a_1_0 = S_1_0 - S_9}}}$

now substituting the value of $S_1_0 = 300 \:\& \:S_9 = 270$ as given

$\implies a_1_0 = 300 - 270$

$\implies \bold{a_1_0 = 30}$

Thus, the value of a₁₀ is → 30.

--------------------------------------------------------------------------------

Also View:

For an AP if s10 = 150 and s9 = 126, t10 = ?

https://brainly.in/question/7229373

Prove that Sn - Sn-1 = an

https://brainly.in/question/8118496