Question

If S10=50 , a=0.5 , then find d?

Answer 1

given that s10 = 50 and a= 0.5

we know that

sn = n/2(2a+(n-1)d)
given s10= 50 so

50 =10/2(2×0.5+(10-1)d)

50 = 5 (1+9d)

50-5 = 9d

45 = 9d

45/9 = d

5 = d

i:e d= 5

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Answer 2

Sn = n/2 [ 2a + ( n - 1) d]

S10 = 10/2 [2× 0.5 + ( 10-1 ) d]

50 = 5 ( 1 + 9d)

50/5 = 1 + 9d

10 -1 = 9d

9 = 9d

9/9= d

:- d = 1 ans

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