if S31=186 then t16=?
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Answered by
4
Step-by-step explanation:
if S31=186 then we have
31/2(2a+30d)=186
or 1/2(2a+30d)=6
=(2a+30d)=12
=(a+15d)=6------(1)
Now, t16= a+(n-1) ×d
=t16=a+(16-1)×d
=t16=a+15d
So from (1) equation we get, t16=6
Answered by
0
Step-by-step explanation:
if S31=186 then we have
31/2(2a+30d)=186
or 1/2(2a+30d)=6
=(2a+30d)=12
=(a+15d)=6------(1)
Now, t16= a+(n-1) ×d
=t16=a+(16-1)×d
=t16=a+15d
So from (1) equation we get, t16=6
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