If sac theta + tan theta =x
express cosec ² in terms of x.
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Step-by-step explanation:
We have,
secθ+tanθ=x ……. (1)
(secθ−tanθ)
(secθ+tanθ)(secθ−tanθ)
=x
(secθ−tanθ)
(sec
2
θ−tan
2
θ)
=x
We know that
sec
2
θ−tan
2
θ=1
Therefore,
(secθ−tanθ)
1
=x
secθ−tanθ=
x
1
……. (2)
On adding the equation (1) and (2), we get
2secθ=x+
x
1
2secθ=
x
x
2
+1
secθ=
2x
x
2
+1
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