if saraya were younger by 5 years than what she really is ,then the square of her agein years would have been 11 more than five times her actual age what is her age now
Answers
Answered by
4
Hey mate!
Here's your answer!!
Let Saraya's actual age be x.
5 years back Saraya's age = x -5
According to the question,
(x - 5)² = 11 + 5x
x² + 25 - 10x = 11 + 5x
x² + 25 - 10x - 11 - 5x = 0
x² - 15x + 14 = 0
x² - 14x - x + 14 = 0
x (x-14 ) -1 (x-14) = 0
(x -14) (x -1) = 0
x = 1
x =14
X can't be 1 because if x = 1,
5 years back her age would be 1 -5 = -4
But age cant be negative,
Therefore,
Her actual age is 14.
Here's your answer!!
Let Saraya's actual age be x.
5 years back Saraya's age = x -5
According to the question,
(x - 5)² = 11 + 5x
x² + 25 - 10x = 11 + 5x
x² + 25 - 10x - 11 - 5x = 0
x² - 15x + 14 = 0
x² - 14x - x + 14 = 0
x (x-14 ) -1 (x-14) = 0
(x -14) (x -1) = 0
x = 1
x =14
X can't be 1 because if x = 1,
5 years back her age would be 1 -5 = -4
But age cant be negative,
Therefore,
Her actual age is 14.
Similar questions