Question

If sec 0+tan 0= m, show that m² -1 m² +1 =sin 0.​

Answer 1

Answer:

If sec 0+tan 0= m, show that m² -1 m² +1 =sin 0.

Step-by-step explanation:

thanku bro jai Hind

Answer 2

Step-by-step explanation:

sec A + tan A = p.

(SinA +1)/CosA= p

1+Sin A= p Cos A

squaring both sides

1+2SinA+ (SinA)^2= (p Cos A )^2

converting Cos A into Sin A and rearranging equation and get quadratic equation then

SinA= has two value -1 and 1-p^2/1+p^2

as value of -1 make

Sec A+ Tan A = undefined hence value of

Sin A=1-p^2/1+p^2

$\huge \underbrace \mathfrak \red{Pls follow꧂}$