Question

If sec 0 + tan 0 = p, show that sec 0 - tan 0 =1/p. Hence, find the values of cos 0 and tan 0.​

Answer 1

Answer:

USING THE GIVEN EQUATIONS,BY SOLVING THROUGH ELIMINATION,YOU CAN EASILY GET VALUES OF tan N sec.....From that you can get the value of COS aslo

Step-by-step explanation:

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$sec ^{2} a - tan^{2}a = 1 \\ ( sec(a) - \tan(a))( \sec(a) + \tan(a)) = 1 \\ ( \sec(a) \: - \tan(a))(p) = 1 \\ therefore \: sec(a) - tan(a) = \binom{1}{p}$

Answer 2

Step-by-step explanation:

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