Question

. If sec 0 + tan 0 = p, then find the value of cosec 0.
WRITTEN ANSWER WILL BE SELECTED AS BRAINLIST....​

Answer 1

Answer:

Given :

sec A + tan A = p

I am replacing p by ' k '

sec A + tan A = k

We know :

sec A = H / B   & tan A = P / B

H / B + P / B =  k / 1

H + P / B =  k / 1

So , B = 1

H + P = k

P = k - H

From pythagoras theorem :

H² = P² + B²

H² = ( H - k )² + 1

H² = H² + k² - 2 H k + 1

2 H k = k² + 1

H = k² + 1 / 2 k

P = k - H

P = k² - 1 / 2 k

Now write k = p we have :

Base = 1

Perpendicular P = P² - 1 / 2 P

Hypotenuse H = P² + 1 / 2 P

Value of cosec A = H / P

cosec A =  P² + 1 / 2 P / P² - 1 / 2 P

cosec A = P² + 1 / P² - 1

Therefore , we got value .

Answer 2

Answer:

cosec0 = 1/p . sec0-1

Step-by-step explanation:

Given,

sec0 + tan0 = p

1/cos0 + sin0/cos0 = p

(1 + sin0)/ cos0 = p

1 + sin0 = p cos0

sin0 = p cos0 -1

1/ cosec0 = p cos0 -1

so,

cosec0 = 1 / (p cos0 - 1)

cosec0 = 1/p . sec0-1