Question

If sec 0 + tan 0 = x, obtain the values of sec ,
tan 0 and sin e​

Answer 1

Answer:

sec0= (x^2+1)/2x, tan0= (x^2-1)/2x, sin0= (x^2-1)/(x^2+1)

Step-by-step explanation:

sec^2O-tan^20=1

sec0 -tan0= 1/x

Adding, sec0 + tan0 & sec0- tan0, we get,

2 sec0= x+1/x

sec0= x^2+1/2x

Subtracting, sec 0 + tan 0 & sec0 -tan0, we get

2 tan0= x-1/x

tan0= x^2-1/2x

As, sec 0= x^2+1/2x

Thus, cos 0 =1/sec0 = 2x/ x^2+1

Also, tan0 = sin0/cos0

Thus, sin0 = tan0× cos0 = x^2-1/x^2+1

Hope it helps!!!