if (secθ-1) (secθ+1) =1/3, then cot θ = OPTIONS (1)√3 (2)1/√3
(3)2/√3 (4)√2/3
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1
Answer:
( sec theta - 1 ) ( sec theta+1)
=( sec theta )^2-(1)^2
=sec theta^2-1
=tan^2 theta
so cot^2 theta =1/ tan^2 theta
cot^2 theta = 1/1/3
cot^2 theta =3
cot theta =√3
Answered by
1
Answer:
OPTION 1 - root 3
Step-by-step explanation:
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