if sec 13/12 ,find the value of other trigonometric ratios
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17
here is your answer by Sujeet.
sec=13/12
by using pytogoras theorem,
h²=p²+b²
13²=12²+b²
b²=13²-12²
b²=169-144
b²=25
b=√25
b=5
then,.
Sin=p/h=12/13
Cos=b/h=5/13
tan=p/b=12/5
cosec=h/p=13/12
sec=h/b=13/5
cot=b/p=5/12
that's all.........
sec=13/12
by using pytogoras theorem,
h²=p²+b²
13²=12²+b²
b²=13²-12²
b²=169-144
b²=25
b=√25
b=5
then,.
Sin=p/h=12/13
Cos=b/h=5/13
tan=p/b=12/5
cosec=h/p=13/12
sec=h/b=13/5
cot=b/p=5/12
that's all.........
sholehashah:
okh
Answered by
16
Given that,
__________
We have to find,
__________
Solution,
We know that ,
So,
___________
Applying pythagoras property-
____________
____________
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