Question

If sec Ɵ = -13/5 and Ɵ lies in second quadrant, find tan2Ɵ​

Answer 1

Step-by-step explanation:

since secθ are negative in 2nd quadrant so

sec(180°-θ)= -13/5

secθ = -(-13/5)

secθ = 13/5 = h/b

through the construction of right angled triangle given above :

then tanθ = p/b = 12/5

since tan2θ = 2tanθ/(1-tan²θ)

tan2θ = 2×12/5/(1-12²/5²)

tan2θ = 120/119