Question

If sec θ = 13/5 then find sin θ

Answer 1

Answer:

3

Step-by-step explanation:

ANSWER

secθ=

5

13

secθ=

B

H

=

5

13

Using Pythagoras Theorem,

H

2

=P

2

+B

2

13

2

=P

2

+5

2

P

2

=144

P=12

Now,

4sinθ−9cosθ

2sinθ−3cosθ

=

4(

13

12

)−9(

13

5

)

2(

13

12

)−3(

13

5

)

=

13

48−45

13

24−15

= 3

Answer 2

Answer:

sec theta = hypotenuse/adjacent

sin theta=opp/hyp

hyp=13

adj=5

opp=√13^2-5^2

√169-25=√144=12

sin theta =12/13