Question

if sec=13/5 where 270 <o< 360°
find the value of 2 sin theta -3 cos theta ÷
3 sin theta + 9 cos theta​

Answer 1

Sec=13/5

hypotenuse/base=13/5

Base=5, perpendicular=12, hypotenuse=13

A. T. Q

24/13-15/13÷36/13+45/13

9/13÷81/13

1/9=answer