if sec^2(a)=4xy/(x+y)^2 prove that x=y and x is
not equal to 0
Answers
Answered by
69
THIS IS A QUESTION ASKED IN IIT-JEE
WE KNOW THAT sec^2(a)>=1
hence 4xy/(x+y)^2>=1
hence,4xy>=(x+y)^2
which gives (x-y)^2<=0
thus only equality will hold since a square term can't be zero
hence (x-y)=0 i.e.x=y
and x or y can't be zero because sec^2(a) can't be zero
WE KNOW THAT sec^2(a)>=1
hence 4xy/(x+y)^2>=1
hence,4xy>=(x+y)^2
which gives (x-y)^2<=0
thus only equality will hold since a square term can't be zero
hence (x-y)=0 i.e.x=y
and x or y can't be zero because sec^2(a) can't be zero
Answered by
37
Answer:
hi
@aniket the answer posted by you is wrong u are saying that 4xy>=(x+y)^2
this is wrong let x = 4 and y = 2
4xy = 4 x 4 x 2 = 32
and
(x+y)^2 = (4+2)^2= 36
Step-by-step explanation:
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