If sec =√2 find 3cot theta+ 2 sin² theta /tan ² theta - cos ² theta
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1
Answer:
5
Step-by-step explanation:
sec theta= root 2
therefore cos theta = 1/root 2
theta = 45 degree
now
3cot theta +2sin square theta/(tan square theta - cos square theta)=
(3 × 1) + {2× 1/2}/1 -1/2=
3+ 1/1/2=
3+ 2=5. Thank you. I derived the fractions from these ratios.
cot 45 =1
sin 45= 1/ root 2 sin square 45= 1/2
cos 45 = 1/ root 2 cos square 45= 1/2
tan 45= 1
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