Math, asked by 19088875, 2 months ago

if sec^2 theta (1 + sin theta) (1 - sin theta) =
a. cos theta
b. 1/cos theta
c. 1
d. 1/sin theta​

Answers

Answered by Harshshahi19
1

Answer:

answer is 1

 { \sec(theta) }^{2} (1 +  \sin(theta))(1 -  \sin(theta)) =  \frac{1}{ { \cos(theta) }^{2} } \times (1 -  { \sin(theta) }^{2}) \\  \frac{1}{ { \cos(theta) }^{2} } \times  { \cos(theta) }^{2} = 1

Step-by-step explanation:

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Answered by princeparth4u
0

Answer:

(sec^2 theta) (1 - sin^2 theta)

(sec^2 theta) (cos^2 theta)

(sec^2 theta) (1/sec^2 theta)

= 1

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