Question

If Sec ^2 theta +tan^2theta=13/12.so sec^4 theta-tan^4theta=?

Answer 1

Answer:

Step-by-step explanation:

sec²Θ +tan²Θ =13/12-------------(1)

we know that sec²Θ -tan² =1-------------------(2)

multiplying (1) ×(2)

∴(sec²Θ + tan²Θ )(sec²Θ -tan²Θ)=13/12

⇒ sec⁴Θ -tan⁴Θ =13/12