If sec 2A = cosec (A – 27°) where 2A is an acute angle, find the measure of ∠A.
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Answer:
2A is measure of acture angle 2A∠90
∘
⇒A∠45
∘
sec2A=cosec(A−42)
cos(2A)
1
=
sin(A−42)
1
sin(A−42)=cos(2A)=sin(90−2A)
(∵2A∠90
∘
)
⇒sin(A−42)=sin(90−2A)
⇒A−42=90−2A
3A=132
A=
3
132
=44
∘
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