if sec 2a= cosec(A-28°) where 2a is an acute angle find the measure of angle A
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Sec 2A= Cosec (A-28)
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Sec2A=Cosec(A-28) Cosec( 90-2A) = Cosec(A-28) [ 2A is an acute angle] 90-2A = A-28. 90+28 = A+2A. 108 = 3A. 16= A
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Answer:
Step-by-step explanation:sec2a=cosec{90-theta)
let theta =a-28
cosec(90-62)=sec2a
sec62=sec 2a
2a=62
a=31
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Sec 2a =cosec(A-28)
where 2a is an acute angle
so ;
sec(90-2a)=Cosec(A-28)
cosec( 90-2a) = cosec ( A - 28)
90 - 2a = A- 28
-2a -a = -90-28
-3a = -108
a = 36
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