If sec 2A = cosec (A - 30°), 0º < 2A < 90°, then find the value of A.
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Answer:sec 2A = cosec (A -30)
cosec(90-2A)=cosec(A-30)
90-2A=A-30
120=3A
A=40
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Step-by-step explanation:
Answered by
0
Answer:
Step-by-step explanation:
the value of Angle A:
Step-by-step explanation:
According to the question we get,
sec2A = cosec(A - 30°)
We know that sec 2A = cosec(90° - 2A)
Therefore we get,
sec2A = cosec(A - 30°)
⇒cosec(90° - 2A) = cosec(A - 30°)
Crossing taking inverse of cosec in both LHS and RHS, we get:
90° - 2A = A - 30°
⇒90 ° + 30° = 2A+A
⇒120° = 3A
⇒ 40° = A
Thus solving we get,
The angle A is 40°
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