Question

If sec 2A = cosec (A − 42°), where 2A is an acute angles, find the value of A.

Answer 1

SOLUTION :  

Given : sec 2A = cosec(A − 42°) and 2A  is acute angle.

sec 2A = cosec(A − 42°)

sec 2A = sec{90–(A − 42°)}

[sec (90 - θ) = cosec θ]

sec 2A = sec{90– A + 42°}

sec 2A = sec{132°– A}

On equating both sides,

2A = {132°– A}

2A + A = 132°

3A = 132°

A = 132/3

A = 44°

Hence, the value of A is 44° .

HOPE THIS ANSWER WILL HELP YOU…

Answer 2

ĀNSWĒR ⏬⏬


Given ▶2A = cosec (A − 42°),

90+42=2A + A

132= 3 A

A= 132/3

A= 44



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#Nishu HARYANVI ♠