Question

if sec^2theta (1 + sin theta) (1- sin theta) = k, then k =?

Answer 1

Hey there
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The correct answer is;
k = sec²t (1+sint) (1−sint)
k = sec²t (1−sin²t)
k = sec²t − tan²t
k = 1

k = sin²t cos²t (1+tan²t)(1+cot²t)
k = sin²t (1+cot²t) * cos²t (1+tan²t)
k = (sin²t+cos²t) * (cos²t+sin²t)
k = 1

5x = sect, 5/x = tant
5(x² − 1/x²)
= 25/5 (x² − 1/x²)
= 1/5 (25x² − 25/x²)
= 1/5 (sec²t − tan²t)
= 1/5


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Hope this helps you
By jerman

Answer 2

k will be equal to 1