Question

If sec 34° = x then find the value of cot? 56° + cosec 56º.​

Answer 1

Answer:

x+√(x^2 -1)

Step-by-step explanation:

cot theta =tan(90-theta)

cosec theta=sec(90-theta

use this formula

Answer 2

Answer:

Correct question

If sec 34° = x then find the value of cot² 56° + cosec 56º.

Step-by-step explanation:

Sol.

$\sec {34}^{0} = x$

$⟹ \sec( {90}^{0} - {56}^{0} ) = x$

$⟹cosec {56}^{0} = x$

$∴ \: \: \: cot {}^{2} {56}^{0} + coeec {56}^{0}$

$= cosec ² \: 56 - 1 + cosec \: {56}^{</p><p>0}$

$= {x}^{2} + x - 1.$

2x² - 1