Question

if sec 4 is equal to cosec a - 20 where food is an acute angle find the value of a

Answer 1

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$

====> As we know

$\boxed{sec \theta = cosec (90- \theta)}$

====> Cosec (90 - 4A) = cosec (A -20)

==>
$\cancel{cosec} \: (90 - 4a) \: = \cancel{cosec} \: (a - 20)$
===> -4a -a = -20 -90

==> -5a = -110

===>
$a = \frac{110}{5}$

==>

$\red{ \boxed{ \underline{ \: the \: value \: of \: a \: is \: 22}}}$

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$
$<b>$
we know that :-

secθ=cosec(90−θ)​ 

➡ Cosec (90 - 4A) = cosec (A -20)

➡ -4a -a = -20 -90

➡ -5a = -110

➡a=22°