Question

If sec(4a+40)=coseca,where a and (4a+40) are accute angles ,find the value of a

Answer 1

Hi mate !!

Here's your answer !!

We know the identity that,

Sec Ф = Cosec ( 90 - Ф )

=> Sec ( 4a + 40 ) = Cosec a

= Sec ( 4a + 40 ) = Sec ( 90 - a )

Sec gets cancelled on both sides. After that we get,

= 4a + 40 = 90 - a

= 4a + a = 90 - 40

= 5a = 50

=> a = 50 / 5 = 10

Hence a = 10°.

Hope my answer helped !!

Cheers !!