if sec 4a = cosec ( A - 20°) where 4A is an acute angle , find the value of A
Answers
Answered by
26
sec4A=cosec(A-20°)
cosec(90°-4A)=cosec(A-20°)-------[sec=cosec(90°-A)]
Comparing only angles
90°-4A=A-20°
-4A-A=-20-90
-5A=-110
A=110/5
A=22°
cosec(90°-4A)=cosec(A-20°)-------[sec=cosec(90°-A)]
Comparing only angles
90°-4A=A-20°
-4A-A=-20-90
-5A=-110
A=110/5
A=22°
Answered by
12
Hi,
______________________________
This is related to Trigonometric Ratios of
Complementary Angles,
Two angles are said to be complementary
if their sum equals 90 degrees.
We know that ,
Cosec ( 90 - x ) = Sec x ----( 1 )
__________________________________
Sec ( 4A ) = Cosec ( A - 20 )
Cosec ( 90- 4A ) = Cosec ( A - 20 )
[ from ( 1 ) ]
90 - 4A = A - 20
90 + 20 = A + 4A
110 = 5A
5A = 110
A = 110 / 5
A = 22
Therefore,
The required angle = A = 22 degrees.
I hope this helps you.
:)Plzzzz marks me As BRILLIANIST
apoorvachandhu:
Long answer yar
Similar questions