if sec 4a = cosec ( A - 20°) where 4A is an acute angle , find the value of A
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12
Here is ur answer
Hi,
______________________________
This is related to Trigonometric Ratios of
Complementary Angles,
Two angles are said to be complementary
if their sum equals 90 degrees.
We know that ,
Cosec ( 90 - x ) = Sec x ----( 1 )
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Sec ( 4A ) = Cosec ( A - 20 )
Cosec ( 90- 4A ) = Cosec ( A - 20 )
[ from ( 1 ) ]
90 - 4A = A - 20
90 + 20 = A + 4A
110 = 5A
5A = 110
A = 110 / 5
A = 22
Therefore,
The required angle = A = 22 degrees.
I hope this helps you.
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Answered by
5
sec4A=cosec(90-4A)--(1)
sec4A=cosec(A-20)---(2)
From 1 and 2,
cosec (90-4A)=cosec(A-20)
90-4A=A-20
4A+A=90+20
5A=110
A=110÷5
A=22
sec4A=cosec(A-20)---(2)
From 1 and 2,
cosec (90-4A)=cosec(A-20)
90-4A=A-20
4A+A=90+20
5A=110
A=110÷5
A=22
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